A combining network driven by multiple voltage sources as shown in the figure of Theorem 1 is equivalent to the same network driven by a single voltage source as shown below.

*Theorem 2.* A combining network driven by multiple voltage sources as shown in
the figure of Theorem 1 is equivalent to the same network driven by a
single voltage source as shown above when

\begin{equation} \label{eq:vefv} v_{efv} = \sum_{k = 1}^{M} v^{\langle k \rangle}_{src} \end{equation}

and all the branch admittances are identical

\begin{equation} \mathbf{Y_{b}} = \mathbf{Y}_{b}^{\langle 1 \rangle} = … = \mathbf{Y}_{b}^{\langle k \rangle} = … = \mathbf{Y}_{b}^{\langle M \rangle} \end{equation}

*Proof.* Using the same method for solving for the load voltage \( v_{load} \) as in
Theorem 1 the load voltage of the network of the above single source equivalent network is

\begin{equation} v_{load} = a_{outer} v_{efv} \sum_{k = 1}^{M} a^{\langle k \rangle}_{inner} \end{equation}

If all the branch admittances are identical and \( v_{efv} \) is defined as (\ref{eq:vefv}), then

\begin{equation} \label{eq:equivsrc} v_{load} = a_{outer} M Y_{b_{21}} \sum_{k = 1}^{M} v^{\langle k \rangle}_{src} \end{equation}

and (\ref{eq:equivsrc}) is equivalent to the \( v_{load} \) equation from Theorem 1 when the branch admittances are the same.

*Corollary.* The proof for current source drive is equivalent to the above by making the H-parameter
substitutions from the Corollary to Theorem 1 and

\begin{equation} v_{efv} = i_{efv} \end{equation}

into (\ref{eq:equivsrc}).